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6x^2-2=7
We move all terms to the left:
6x^2-2-(7)=0
We add all the numbers together, and all the variables
6x^2-9=0
a = 6; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·6·(-9)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{6}}{2*6}=\frac{0-6\sqrt{6}}{12} =-\frac{6\sqrt{6}}{12} =-\frac{\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{6}}{2*6}=\frac{0+6\sqrt{6}}{12} =\frac{6\sqrt{6}}{12} =\frac{\sqrt{6}}{2} $
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